Answer:
The value of A33 = 398 ....
Step-by-step explanation:
Given:
The Arithmetic sequence A1,A2,A3,A4 ,62, 74, 86, 98
What is the value of A33?
T(n) =a +(n-1)d
where d = 12
n = 8
T(8)=a+(8-1)*12
T(8)=a+7*12
T(8)=a +84= 98
a=98-84
a= 14
Now,
T(33)= 14+(33-1)*12
=14+(32)*12
= 14+384
T(33)= 398
The value of A33 = 398 ....
