Answer:
[tex]\lim_{x \to 0} \frac{x^2}{sinx}=0[/tex]
Step-by-step explanation:
[tex]f(-0.03)=-0.0300\\f(-0.02)=-0.0200\\f(-0.01)=-0.0100\\f(0.01)=0.0100\\f(0.02)=0.0200\\f(0.03)=0.0300[/tex]
As the Left side of the function is approaching 0 as it gets closer to x=0 and the Right side is also approaching 0 as it gets closer to x=0, the limit would be 0.
