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Write the equation 8y = x – 0.8 in standard form. Identify A, B, and C.
480x + 5y = –48 where A = 480, B = 5, and C = 96

480x – 1y = –48 where A = 480, B = –5, and C = 96

5x – 480y = 48 where A = 5, B = –480, and C = 96

1x + 96y = 9.6 where A = 1, B = –96, and C = 0.8

Respuesta :

calculista

Answer:

[tex]5x-40y=4[/tex]

Step-by-step explanation:

we know that

The standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers

In this problem we have

[tex]8y=x-0.8[/tex]

Multiply by 5 both sides

[tex]40y=5x-4[/tex]

Adds both sides 4

[tex]40y+4=5x[/tex]

Subtract 40y both sides    

[tex]4=5x-40y[/tex]

Rewrite

[tex]5x-40y=4[/tex] ----> equation of the line into standard form

A=5

B=-40

C=4

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