Answer:
0.1589 mol ≅ 0.16 mol.
Explanation:
- Knowing that the no. of moles can be calculated using the relation:
no. of moles (n) = mass/molar mass
mass of Al(OH)₃ = 12.4 g & molar mass of Al(OH)₃ = 78.01 g/mol.
∴ n = mass/molar mass = (12.4 g)/(78.01 g/mol) = 0.1589 mol ≅ 0.16 mol.
