sarabara18
sarabara18 sarabara18
  • 26-02-2019
  • Mathematics
contestada

What are the domain restrictions of the function f(x) = the quantity of x squared plus 6x plus 9, all over 3x plus 15.

Respuesta :

jimrgrant1 jimrgrant1
  • 26-02-2019

Answer:

x = - 5

Step-by-step explanation:

Given

f(x) = [tex]\frac{x^2+6x+9}{3x+15}[/tex]

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

solve : 3x + 15 = 0 ⇒ 3x = - 15 ⇒ x = - 5 ← excluded value

Domain x ∈ R , x ≠ - 5

Answer Link

Otras preguntas

simplify the expression 5 + 2 ×[(2+2)×5+5]
What kind of tumor grows in only one part of the body?
Name an arc longer than a semicircle for circle O
Many new restaurants have opened in Collegetown in recent years. Given this change in supply, what type of demand would result in a larger drop in prices for re
Why was domestication an important advancement in the hunter-gatherer culture?
In what ways might these bodies of water have influenced life in medieval europes
anna wants to buy a one carat diamond. One carat equals 200 mg. If a diamond is 0.600 carat, what is the mass of the diamond in ounces? 1 kg=2.205 pounds 1 poun
State as many properties as you can about a rhombus
Pujols lumber yard has a current accounts receivable balance of $527,167. credit sales for the year just ended were $5,938,261. requirement 1: what is the recei
According to this passage what was the purpose of th anglo Russian entente