natlindylooohoo7 natlindylooohoo7
  • 25-02-2019
  • Mathematics
contestada

what are the zeros of 2x^2-6x-8

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 25-02-2019

Answer:

x=4   x=-1

Step-by-step explanation:

2x^2-6x-8

Factor out a 2

2(x^2 -3x-4)

What 2 numbers multiply to -4 and add to -3

-4 *1 = -4

-4+1 = -3

2(x-4)(x+1)

Set this equal to zero to find the zero's

2(x-4)(x+1) =0

Using the zero product property

x-4 =0     x+1 =0

x=4   x=-1

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