Try this solution:
Step-by-step explanation:
1) for zeros of the function: x²-6x-7=0; ⇒ x₁=7; x₂= -1.
2) for the vertex of the function: x₀= -b/2a, where a;b;c - numbers from ax²+bx+c=0 (from x²-6x-7=0).
x₀=6/2=3;
y₀= (4ac-b²)/4a; ⇒ y₀= -16.
It means, the coordinates of the vertex are (3;-16).
