edward85 edward85
  • 23-01-2019
  • Mathematics
contestada

(Y^3 - 125) divided (y -5)

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 23-01-2019

Answer:

(y^2+5y+25)

Step-by-step explanation:

(y^3 - 125) ÷ (y -5)

Factor the first term.  This is the difference of cubes

a^3 – b^3 = (a – b)(a^2 + ab + b^2)

Let a=y    and b = 5  (5^3 =125)

(y^3-125) = (y-5) (y^2+5y+25)

Substitute this back into the original equation

(y-5) (y^2+5y+25)

----------------------------

(y-5)

The y-5 term cancels

(y^2+5y+25)

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