Answer:
3z(3w - 2)(3w + 2)(9w² + 4)
Step-by-step explanation:
take out a common factor 3z from both terms
= 3z(81[tex]w^{4}[/tex] - 16)
81[tex]w^{4}[/tex] - 16 ← is a difference of squares
• a² - b² = (a - b)(a + b)
81[tex]w^{4}[/tex] = (9w²)² → a = 9w² and 16 = 4² → b = 4
= 3z(9w² - 4)(9w² + 4)
9w² - 4 ← is also a difference of squares with a = 3w and b = 2
= 3z(3w - 2)(3w + 2)(9[tex]w^{4}[/tex] + 4)
