reyes01523 reyes01523
  • 23-09-2018
  • Mathematics
contestada

Divide (16x^2 -20+9)÷(4x-3)

Respuesta :

Piinoy
Piinoy Piinoy
  • 23-09-2018

[tex]\frac{16x^2-20+9}{4x-3}[/tex]

Simplify.

[tex]\frac{4x^2-11}{x-3}[/tex]

Divide (subtract the exponent from the top to the bottom).

[tex]\frac{4x-11}{-3}[/tex]

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