zii60 zii60
  • 24-07-2018
  • Mathematics
contestada

The graph represents the function f(x)=x^2+3x+2

Respuesta :

rejkjavik rejkjavik
  • 30-07-2018

we are given

[tex] f(x)=x^2+3x+2 [/tex]

x-intercept:

we can set f(x)=0

and then we can solve for x

[tex] x^2+3x+2=0 [/tex]

[tex] (x+1)(x+2)=0 [/tex]

[tex] x=-1,x=-2 [/tex]

y-intercept:

now, we can plug x=0

[tex] y=0^2+3(0)+2 [/tex]

[tex] y=2 [/tex]

Vertex:

[tex] x=-\frac{b}{2a} [/tex]

[tex] x=\frac{-3}{2*1} [/tex]

[tex] x=-\frac{3}{2} [/tex]

[tex] f(-\frac{3}{2} )=(-\frac{3}{2} )^2+3*(-\frac{3}{2} )+2 [/tex]

[tex] y=-0.25 [/tex]

so, vertex is (-1.5 , -0.25)

so, we can draw graph

Ver imagen rejkjavik
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