kaykaymhut
kaykaymhut kaykaymhut
  • 24-07-2018
  • Mathematics
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PLEASE HELP ASAP!!!! (Picture included)

PLEASE HELP ASAP Picture included class=

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DeanR
DeanR DeanR
  • 24-07-2018

We write the quadratic formula

[tex] x = \dfrac{-b \pm \sqrt{b^2 -4ac}}{2a}[/tex]

and substitute,

[tex] x= \dfrac{- -3 \pm \sqrt{(-3)^2-4(2)(-4)}}{2(2)} = \dfrac{3 \pm \sqrt{41}}{4}[/tex]

Choice C




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