Respuesta :

[tex] \bf \begin{cases}
f(x)=2x+1\\
g(x)=x^2-10\\
f(~~g(x)~~)=2[g(x)]+1
\end{cases}
\\\\\\
g(3)=(3)^2-10\implies g(3)=9-10\implies g(3)=-1
\\\\\\
f(~~g(3)~~)=2[g(3)]+1\implies f(~~g(3)~~)=2[-1]+1
\\\\\\
f(~~g(3)~~)=-2+1\implies f(~~g(3)~~)=-1 [/tex]

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