Respuesta :

ktreyb
2x + 3 ≥ 7
2x ≥ 7 - 3
2x ≥ 4
x ≥ 4 / 2
x ≥ 2

2x + 9 > 11
2x > 11 - 9
2x > 2
x > 1

Those are your two inequalities, now we must find one that satisfies both. Combine them together you get:

1 < 2 ≤ x

That last inequality becomes your answer. 

x ≥ 2 makes both statements true. 

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