Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

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axelkatracho181 axelkatracho181

22-06-2018
Mathematics

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Line JK passes through points J(–4, –5) and K(–6, 3). If the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?

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musicluvr31658 musicluvr31658 · Answer 1 · 2018-07-01T05:55:55+02:00

The value of "b" is the y-intercept.

In order to figure out slope-intercept form you need 1 coordinate and the slope.
1) Find the slope, using the 2-point slope formula: "m= y2-y1 / x2-x1".
ex. m= -5 - 3 / -4 - -6 (simplify)---> m= -4

2) Fill in the blanks for point-slope formula: "y - y1 = m (x - x1)"
(choose one coordinate, it doesn't matter which one)
ex. y - -5 = -4 (x - -4)

3) Then use basic algebra to simplify.