KaylinH KaylinH
  • 25-05-2018
  • Mathematics
contestada

solve the quadratic using the quadratic formula
[tex]5x {}^{2} + 12x - 2 = 0[/tex]

Respuesta :

gmany
gmany gmany
  • 02-06-2018
The quadratic formula:

[tex]ax^2+bx+c=0\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}[/tex]

We have:

[tex]5x^2+12x-2=0\\\\a=5;\ b=12;\ c=-2\\\\b^2-4ac=12^2-4\cdot5\cdot(-2)=144+40=184\\\\\sqrt{b^2-4ac}=\sqrt{184}=\sqrt{4\cdot46}=2\sqrt{46}[/tex]

substitute

[tex]x_1=\dfrac{-12-2\sqrt{46}}{2\cdot5}=\dfrac{-6-\sqrt{46}}{5}\\\\x_2=\dfrac{-12+2\sqrt{46}}{2\cdot5}=\dfrac{-6+\sqrt{46}}{5}[/tex]
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