The complete question is;
How many Joules of heat energy would be required to raise the temperature of 16.0 g of lead from 25 degrees to its melting point of 327 degrees for a length of time long enough to completely melt the lead.
Specific heat capacity of lead is 0.159 J/gK and the molar enthalpy of fusion is 24.7 J/g
Heat is given by mcΔT
Δ T= 322 ° c = 322 +273 = 595 K
Heat = (16 × 595 × 0.159) + (24.7 × 16 )
= 1513.68 + 395.2
= 1908.88 Juoles
