pinky1112446p7dh9d pinky1112446p7dh9d

22-05-2018
Physics

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If 35 J of work was performed in 70 seconds, how much power was used to do this task?

Respuesta :

limacharliesierra limacharliesierra

22-05-2018

[tex]P = w \times delta \: T[/tex]
P = Power
W = Work
Delta T = Change of Time

So:
P = 35 Joules
Delta T = 70 secs
W = ?

[tex]P = 35 \div 70 \\ P = 0.5 \: watts[/tex]

* Joule/Sec = Watt

Answer: The power used to do this task was 0.5 Watts.

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