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  • 25-04-2024
  • Mathematics
contestada

We have found the following values of the function and its
derivatives.
f(0) = 8
f'(0) = 16
f''(0) = 48
f'''(0) = 192
f⁽⁴⁾(0) = 960
Therefore, the Maclaurin series begins as
f(x) = f(0) + f(0)x + f"(0)/2! x² + f"'(0)/3! x³ + f⁽⁴⁾(0)/4! x⁴ + dots
= , X x + , X x² , X x³ + dotsx⁴ + dots

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