PCl5(g)⇌PCl3(g)+Cl2(g)

Initially, 0.60 mol of PCl5 is placed in a 1.0 L flask. At equilibrium, there is 0.16 mol of PCl3 in the flask.
1)What is the equilibrium concentration of Cl2 ?
2)What is the numerical value of the equilibrium constant, Kc
, for the reaction?